chp2 problem9

# Physics: Principles with Applications

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Unformatted text preview: Solution: The total distance that the jogger covers is 8 lap 0.25 mile/lap = 2 miles. However, the joggers total displacement is 0 miles, since she finishes at the same place she starts. (a) Since speed is distance/time, the jogger's speed is 1610 m 1 min 2.0 mi = 4.3 m/s. 12.5 min mi 60 s (b) Since the jogger's total displacement is 0.0 m, her average velocity is also 0.0 m. ...
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