chp2 problem9

Physics: Principles with Applications

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: Solution: The total distance that the jogger covers is 8 lap 0.25 mile/lap = 2 miles. However, the joggers total displacement is 0 miles, since she finishes at the same place she starts. (a) Since speed is distance/time, the jogger's speed is 1610 m 1 min 2.0 mi = 4.3 m/s. 12.5 min mi 60 s (b) Since the jogger's total displacement is 0.0 m, her average velocity is also 0.0 m. ...
View Full Document

Ask a homework question - tutors are online