Aircraft exam 2 page 1.jpg - MEM 425 Midterm 2 John Bav Madsen L = 22 70 0 N Cmo = 06 2 CMcg 6137 deg a = ogden S = 19m VH = 34 a Cut 25 04deg asstring

Aircraft exam 2 page 1.jpg - MEM 425 Midterm 2 John Bav...

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Unformatted text preview: MEM 425 Midterm 2 John Bav Madsen L = 22 70 0 N Cmo = . 06 2 CMcg - - 6137 deg a = . ogden S = 19m ? VH =. 34 a Cut 25 04deg asstring enough power was you could go so just under mach Supplied increasing the angle of atrack, just above the zero lift angle , so if at He angle attack o Skim falls within the allowable boundaries there is no subpanic upper trim Emo + ( 2 ( mcg / Joc a ) in e o trim ( VH ase - (mo 2 ( : 340 . 04 ) - 06 = 26466 1 8135 - b . . - 9. 674 The only angles of whit exists have rogative angles or attack and I there fore produce negative The, and canner maintain level flight....
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