# Well_Engineering.docx - INTERNATIONAL UNIVERSITY OF EAST...

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INTERNATIONAL UNIVERSITY OF EAST AFRICA KAMPALA-UGANDA DEPT OF PETROLEUM ENGINEERING WELL ENGINEERING COURSE WORK BY ALFA JONATHAN HUSSEINI REGISTRATION NUMBER: 13/NG/173/BSPE-J YEAR: YEAR 2 SEMESTER 2 DATE: 16 TH APRIL, 2015 DEPARTMENT: Bsc PETROLEUM ENGINEERING

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1 You are given the following information/data on exploration well “X-1”;  Mud line (ML) is 1,300m below mean sea level (BMSL)  TD at 2,550m TVD SS The rig selected to drill the ‘‘X-1’’ well has a rotary table to MSL elevation of 25 metres. The conductor hole will be drilled with a 36” bit and 42” hole opener. The spacing between the hole opener and the bit is 3 metres. A seven joint 36”, 1.5” wall thickness conductor casing will be run on 5.1/2” drillpipe having an adjusted weight of 25.2 lb/ft. The plan is to leave a 5 metre, 42” diameter rat hole below the float shoe and have the top of the conductor 2.5 metres above the seabed. Each joint of conductor pipe/casing is 12 metres long. The conductor casing will be cemented to the seabed with 15.8 ppg neat cement slurry. The cement inside the conductor will be displaced to within 5 metres of the shoe. a) Determine the TD of the 36” conductor hole measured from the rig’s rotary table (TVD BRT). [ 04 marks ] b) Calculate the tension in the drill pipe joint at the rotary table just prior to the conductor shoe entering the 42” hole. You may assume the conductor/drillpipe is full of seawater. Density of sea water is 8.6 ppg and density of steel is 65.5 ppg. Ignore the weight of the conductor running tool assembly. [ 09 marks ] Hint; Plain End weight of the casing can be computed from; c) After drilling the 42” hole to section TD, a calliper log was run and it was concluded that the hole had washouts giving an equivalent hole size 15% more than the gauge hole. Calculate the number of
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