Midterm Practice Units 1.docx - Midterm Practice Units 1-3 a Curren The stator current s= √ P 2 Q2 =√(54)2 23.8)2=KVA I = s/53VL =(59*10^3 53*520 I

# Midterm Practice Units 1.docx - Midterm Practice Units 1-3...

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Midterm Practice Units 1-3 a. Curren The stator current s = P 2 + Q 2 = ( 54 ) 2 + ( 23.8 ) 2 = KVA I = s/53VL = (59 *10^3)/ 53 *520 I = 65.6 A b. If the following gasoline engines are available—30 hp, 100 hp, and 150 hp—which one is best suited to drive the generator? P = 54 kW ^2 * 10 = 3845 Vam P = 53VL IR = (53*520*60) P = 54kW a. The reactive power supplied by the capacitor bank Xc = 1/2πfc = 1/(2*3.14*140*100*10^-6 = 11.37 Ω = (54 * 10^3)/746 If the generator efficiency is 90 % then the egine power must be more than 72.9/ 0.9 = 90 hp So I would choose 100 hp 14-17 The motor in Problem 14-16 is cooled by circulating 350 gallons (U.S.) of water through the heat exchanger per minute. Calculate the increase in water temperature as the water flows through the heat exchanger. t per Capacitor VL/53*Xc = 520/53*11.37 = IC = 26.4 A Q = 53 VL IC = 53 * 520 * 26.4

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Q = 23.8 = QL a. The reactive the energy in the flywheel at 1800 r/min [kJ] percent of Ra = 5850W/(853)^2 = 8 mΩ Ia = 862 – If = 862 – 10 = 852 A a. Eo = 250 – (852 * 0.0 IL^2XL = (19.61) power generated by the capacitor QL = V^2/ Xc = 200^2/10 = 4000 Vam 13-15.
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