Problem 12.docx - Solution a = 134 250 = 0.536 Descriptive Statistics N 250 Even Sample t p 134 0.536000 95 CI for p(0.472070 0.599066 We have

Problem 12.docx - Solution a = 134 250 = 0.536 Descriptive...

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Solution: a) = 134 / 250 = 0.536 Descriptive Statistics N Even t Sample p 95% CI for p 250 134 0.536000 (0.472070, 0.599066) We have calculated the data by examining the number of population and number of events. We have found that at 95% interval we probability value is getting higher. b) H 0 : P 0 ≤ 0.5 H a : P a > 0.5 N = 250 We have a following formula to calculate the test statistic Descriptive Statistics N Even t Sample p 95% Lower Bou nd for p 250 134 0.536000 0.482007 Test Null hypothesis H₀: p = 0.5 Alternative hypothesis H₁: p > 0.5
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P-Value 0.141 P-Value
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Unformatted text preview: 0.127 The above result is showing that the p-value is clearly greater than the significance level. So the null hypothesis is acceptable. The result is also not accepting the forecasting of company consultant that the half consumer favour its drink over competitor. c) The sample size is = 250 The hypothesis proportion is P = 0.5 So, n(1 - P ) > 5 250 * 0.5 > 5 125 > 5 And, nP > 5 250 * 0.5 > 5 125 > 5 The sample size is good for study because it’s not small....
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