# 46308171_360071401216667_4986535568427974656_n.jpg - 8...

• No School
• AA 1
• 1

This preview shows page 1 out of 1 page.

Unformatted text preview: 8. GIVEN 10 1. GIVEN 10 fx 2X C . = 2 Tir :: : A= LW CK = 2 1 ( 7 ) 10 = 10 (2X ) REQ : a) depth of liquid (y * = 0 .5 Required: dimension CK - 1 ATT - Ck= 43.98 am COLUTION b ) volume (V ) of liquid - 2 - Solution: A= 2 rrh+ 2Tr ? 572 = ( 2 ) (r ) (6 ) + 2Tir? Ans : 6 cm x 43. 98 am ) 2 = 0.5 0 .25 X, = Ift 10 = - 572 + 12 mir + 2 Tir 10.25 0 = - 286 + GTr + TVr 2 = 0.5 V = B h b = GTI C = - 286 y 1 2 ( 1 ) ( 0 : 25 ) (10 ) By QUADRATIC EQUATION. y = 0.25 ( 2.5 ) 1 = 7.004 ( 7 ) 12 = - 13.009 2- 13 recent, V = 1.25 # 3...
View Full Document

• Fall '19

### What students are saying

• As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

Kiran Temple University Fox School of Business ‘17, Course Hero Intern

• I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

Dana University of Pennsylvania ‘17, Course Hero Intern

• The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

Jill Tulane University ‘16, Course Hero Intern