8_5_elimination_using_multiplic.ppt - x 4 y 17 3x 2y 9 Previously we learned how to solve systems of equations by using addition or subtraction which

# 8_5_elimination_using_multiplic.ppt - x 4 y 17 3x 2y 9...

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x y x y 4 1 7 3 2 9 Subscribe to view the full document.

Previously, we learned how to solve systems of equations by using addition or subtraction which eliminated one of the variables. 2 3 1 2 3 6 x y x y This system of equations could be solved by eliminating the y variable through addition. 3 2 1 5 3 9 x y x y This system of equations could be solved by eliminating the x variable through subtraction. x y x y 4 1 7 3 2 9 Since this system of equations can’t be solved by elimination with addition or elimination with subtraction, how can we solve it? If the top equation was multiplied by 3 , then the first term would be 3x . The bottom equation could then be subtracted from the top equation eliminating the variable x . 3 4 3 1 7 3 1 2 5 1 ( ) ( ) x y x y The new system of equations is now: 3 1 2 5 1 3 2 9 x y x y Subscribe to view the full document.

3 1 2 5 1 3 2 9 x y x y Subtract the bottom equation from the top equation. (-) 1 4 4 2 y Solve for y .  • Fall '16
• SANDRA MARSH

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