83E4E37C-311C-4914-AF80-3C9F0FBD0253.jpeg - horizontal so SodaCan Toa V = Ux J= 3.5 m/s dx = Vxt dy = zat Vyiz two dy = 3.5 Lt 7 45 2 9.81 to 3 = t d=

# 83E4E37C-311C-4914-AF80-3C9F0FBD0253.jpeg - horizontal so...

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Unformatted text preview: horizontal, so SodaCan Toa V = Ux J= 3.5 m/s dx = Vxt dy = zat Vyiz two. dy = ( 3.5 ) Lt ) 7- 45 : 2- 9.81 to 3 = t d= 45 m Vyi= 0m/s dy = 45 m t a = -9:81 m / s 2 Vx : 3.5m /sphaistoslost - dy = t= 3s &lt; 2 DMotion at an angle * horizontal velocity is 1Im/s 160-7550 Uyr = 9 constant, ALWAYS ! Vxi = 6. 3 Sin 55 71 a ) hang time = 1. 8s Cos 55 = #1 b) max height: 4.1m hang time c ) range : 1/ m Vix = 9 m/s VAY = Umn/S a = - 9. 81 m / 5 2 Vay = Viy + at 0 = 9 + ( - 9. 8 1)t 0. 92 x 2 - - only one half max height 1.80 ) of the time V fy : 0 m/s v. 2 = Via+ 2ad Range : dx Vy = &quot; . dx: but a = - 9.81 m/s 2 0'= 90+ 2(- 9.81 )d Vx: 6.3 4. 1 = d t= 1.8 Le, 3 . 1.8 dy = 4. 1 m...
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• Fall '19
• Yoshinao Hirai

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