HeatofSub - Chem 124 Winter 2008 Dr. Hascall Name: Partner:...

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Chem 124 Winter 2008 Dr. Hascall Name: Computer Number: Partner: The Heat of Sublimation of Dry Ice Instructions: This report is to be completed by each of you INDIVIDUALLY after performing the experiment with your partner. This report is due at the beginning of class on Thursday January 24 th . You are to fill in this form using Word to create a clear and informative report. To draw attention to your answers, you may want to use color or bold type. Be sure to keep your answers and graphs within the allotted spaces (some resizing may be necessary on your part). You will turn in a hard copy of this report. Calculated Results: Fill in your results of your calculations in the table below. Title the table appropriately! (in space below) Heat of Sublimation of Dry Ice Trial # Heat Energy Exchanged ( q ) Heat of Sublimation (in kJ/mol CO 2 ) 1 13.592 kJ 27.35 kJ/mol 2 10.495 kJ 27.40 kJ/mol 3 8.996 kJ 27.06 kJ/mol Average 11.028 kJ 27.27 kJ/mol Show a sample calculation for each of the following within the provided space: (1) heat energy exchanged ( q ) : q=mC(Tf-Ti) q = 62.594g x 4.184 J/gK x (66.7-14.8) = 13.592 kJ (2) heat of sublimation in kJ/mol of CO 2 Moles of CO2 = m / atomic weight = 21.870 g / 44.01 g/mol = .497 mol Heat of Sublimation = q / moles of CO2 = 13.592 kJ / .497 mol = 27.348 kJ/mol Cluster Results:
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Chem 124 Winter 2008 Dr. Hascall Record the results from the three best trials of each of the other stations in your cluster in the table below. Trial #
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This note was uploaded on 04/01/2008 for the course CHEM 124 taught by Professor Hascall during the Winter '08 term at Cal Poly.

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HeatofSub - Chem 124 Winter 2008 Dr. Hascall Name: Partner:...

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