Captura de pantalla 2019-11-16 a las 23.42.38.png - Part 3 Liquid-Liquid Extraction Theory Illustrate the mechanism(using specific curved arrows to show

Captura de pantalla 2019-11-16 a las 23.42.38.png - Part 3...

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Unformatted text preview: Part 3: Liquid-Liquid Extraction Theory Illustrate the mechanism (using specific curved arrows to show the flow of electrons ) for the reaction that occurred when you added 3.0 M NaOH(aq) to your separatory funnel. For each individual species, indicate 3 4 is in the organic layer, aqueous layer or if it is a precipitate. [3 Marks] Aqueous layer OH Na p- bluic acid ( weak acid ) Sodium hydroxide Conjugate base Conjugate acid proton donor " (strong base ) "proton acceptor Good! only missing the layers that each compound stays in (-1). The un- Illustrate the mechanism (using arrows to show the flow of electrons) for the reaction that occurStayedin the organic charged p-Toluic acid you added 12 M HCI(aq) to your beaker. For each individual species, indicate if it is in the organisybayer, aqueous layer or if it is a precipitate. [3 Marks] Aqueous phase weak base .CPlease clearly show electron arrow proton acceptor strong acid proton donor pushing next time,Second arrow onjugate base vague and appears to be pointing at the O-H bond rather than the oxygen (-0.5) Did not indicate which compound is Explain why the addition of acid (3 M HCI(aq)) or base (3 M" Navi(aq)) will not separate, the neutral compound into the aqueous layer? [1 Mark] . Add the counter ion (Nat and CI-) next time (not penalized as the hy- dronium ion is used It is assumed that a neutral compound will dissolve better in the organic layer than the aqueous solution. Because If we add any of those solutions with, in this case Fluorene a ketone, would undergo condensation reactions catalyzed by both, acids and bases. The neutral compound is not soluble in water, so it remains in the organic layer. The neutral would not react with the acid/base. It would be because neutral compounds dont have ionizable function- al groups, so it cannot be deprotonat- ed/protonated changing their solubility (-1)...
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  • Fall '09
  • GOLL
  • Experiment 1 Chem 266L

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