**Unformatted text preview: **Z [total = 3] (c) P-value = P ( Z > 1.89) = 1 – P ( Z < 1.89) = 1 - .9706 = .0294 [2] (d) Since P-value < .05, we reject H . [2] 017 , 2 3 . 7 . 02 . 96 . 1 ) 1 ( 2 2 = × × =- ≥ p p e z n 0259 . 5497 . 01576 . 645 . 1 54965 . 997 45035 . 54965 . 645 . 1 54965 . ~ ) ~ 1 ( ~ ~ ± = × ± = × ± =-± = n p p k p 0207 . 9793 . 1 ) 04 . 2 ( 1 ) 04 . 2 ( 7 . 39 1 . 179 260 ) 260 ( =-= <-= > = -> = > Z P Z P Z P X P 1 1 1 1 1 1 2 1 1 1 1 0015 . ) 97 . 2 ( 20 7 . 39 1 . 179 7 . 152 ) 7 . 152 ( =-< = -< = < Z P Z P X P 1 rounding doesn’t matter formal statement not required 1 ½ if 3 decimals, 0 if fewer than 3 decimals. exact = .0015 exact = .0208 exact = 253.77 1 exact = .0290 exact = 1.8957 1...

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