Lec 10-28.ppt - CHEN 461 – Fall 2019 CLOSED-LOOP ANALYSIS FOR PROCESSES WITH DEAD TIME CONTROL OF PROCESSES WITH DEAD TIME CONTROLLER PROCESS CONTROL

Lec 10-28.ppt - CHEN 461 – Fall 2019 CLOSED-LOOP ANALYSIS...

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CHEN 461 – Fall 2019 CLOSED-LOOP ANALYSIS FOR PROCESSES WITH DEAD TIME
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CONTROL OF PROCESSES WITH DEAD TIME PROCESS CONTROLLER
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CONTROL OF PROCESSES WITH DEAD TIME PROCESS CONTROLLER
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CONTROL OF PROCESSES WITH DEAD TIME PROCESS CONTROLLER
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Example : P-only Control of a first order process with dead time (FOPDT)
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Example : P-only Control of a first order process with dead time (FOPDT)
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Poles of closed loop system : They are the roots of the equation Infinite number of poles … Example : P-only Control of a first order process with dead time (FOPDT)
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Poles of closed loop system : They are the roots of the equation Infinite number of poles … Example : P-only Control of a first order process with dead time (FOPDT) Stability Analysis ??? Response calculation ???
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CONTROL OF PROCESSES WITH DEAD TIME: Stability Analysis 1) Approximate stability analysis via a rational approximation of the closed loop transfer function
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Unformatted text preview: 2) Exact stability analysis via the Bode stability criterion • Padé approximations [will see that in Chapter 11] • (1,1) • (2,2) • (3,3) …... • (Ν,Ν) Padé approximations of the function e-X With (1,1) Padé approximation of e-θs : common denominator With (1,1) Padé approximation of e-θs : common denominator Approximate stability condition: With (2,2) Padé approximation of e-θs : common denominator : With (2,2) Padé approximation of e-θs : common denominator : Approximate stability condition: CONTROL OF PROCESSES WITH DEAD TIME: Response calculation with MATLAB In the example , for k c = 40, k =0.1, τ =1, θ=0.2 and a unit step change in the set point, 0.5 1 1.5 2 2.5 0.2 0.4 0.6 0.8 1 1.2 1.4 Unit step change in set point, P control with Kc = 40 Time (seconds) Output...
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  • Fall '12
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