# rps20191117_123452.jpg - Data Page The acceleration of the...

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Unformatted text preview: Data Page The acceleration of the mass center a is . 3 By equation ( 1) an ( 3 ) ( F BO = IRD ) - mg j - ( It To ) by = - ml a = by + m Lo 62 4 NOW ( 4 . 62 D - masimo = milo 0 = - 8 simo L 4 . by D ma coso - ( T , + I , ) = - mLo - 6 e use equation ( for solve Tension T2 in the right rope in terms of tension T, in the left Robe . ( FBD - IRD) ( d l t h ] ) x ( - T , b / ) + ( d i t h ] ] x ( - T 2 by ) = Q ( - T , d c o s o + T , h s i m o t T z d c o s Q + [ 2 h sim o ) K - a dcoso - hsimo dcost + hsimo 7 Substitute the value of Tension ( 72 ) in equation (6 mg cosa - Tif + dcoso - Rsimo doso + Rsimo Ti = m ( g cos o + 1 8 2 ] ( d cos o + h simo ] 8 2 d coso...
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