written assignment 1.docx - 1.To find the domain of f(x)= √ x−6 √ x−4 Here in order this equation to be defined first the radicands should be

# written assignment 1.docx - 1.To find the domain of f(x)=...

• Homework Help
• 3

This preview shows page 1 - 3 out of 3 pages.

1.To find the domain of f(x)= x 6 / x 4 Here in order this equation to be defined, first the radicands should be greater or equal to zero. Furthermore, the denominator should not be zero Abramson, J. (2017). x 6 0 x 4 > 0 x≥ 6 x > 4 When we put these x values in the number line, the second one could not satisfy the first equation, however, the first one could satisfy both equations. Therefore, our domain will be [6, ∞). 2. to graph the piecewise function, I have chosen the function: 1/(x 2 -x-6), in order the function to be defined, the denominator should not be equal to zero. x 2 -x-6 0 factoring this (x-3) (x+2) 0 Which is x 3 x≠ 2 Hence, the domain of this function will be, (- ∞ , -2) (− 2,3 ) ( 3 ,∞ ) The graph looks like Subscribe to view the full document.

Graph credit to Desmos graphing calculator. 3. c(x) = 10x+500 a, find c (0) which is b, find c (25) which is C (0) =10(0) +500  Unformatted text preview: c (25) = 10(25) +500 C (0) = 0+500 c (25) =250+500 C (0) = 500 c (25) =750 c, find domain and range for the maximum cost of 1500, ∴ if maximum cost is 1500, C(x) ≤ 1500 , where c(x)= 10x+500 from the question Then 10x+500 ≤ 1500 10x ≤ 1500 − 500 10x ≤ 1000 dividing both sides by 10 x ≤ 100 Therefore, our domain would be from the maximum cost to the fixed cost where zero items are produced. This will be {X|0 ≤x ≤ 100 } The same thing our range will be from the fixed cost with no item and the maximum cost written as {x| 500 ≤x ≤ 1500 } Reference Abramson, J. (2017). Algebra and trigonometry . OpenStax, TX: Rice University. Retrieved from Desmos graphs (n.d.). Retrieved from, ...
View Full Document

• Spring '17

### What students are saying

• As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

Kiran Temple University Fox School of Business ‘17, Course Hero Intern

• I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

Dana University of Pennsylvania ‘17, Course Hero Intern

• The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

Jill Tulane University ‘16, Course Hero Intern