Unformatted text preview: S= distance= 7.6 metres A= acceleration= T= time taken=1.53 seconds U= initial velocity= 0 Acceleration due to gravity: s = 1 2 at 2 + ut s − ut = 1 2 at 2 1 2 at 2 = s − ut at 2 = 2 ( s − ut ) a = 2 ( s − ut ) t 2 a = 2 ( 7.6 − ( × 1.53 ) ) 1.53 2 2 decimal places a = 6.49 ¿ ) metres per second Prac 2: a= (final/0.02-initial/0.02)/(number of dots between final and initial x 0.02) ms-2 final velocity: 10 initial velocity: 6 Lily Mills Acceleration Due to Gravity Practical 10G a = final velocity 0.02 − initialvelocity 0.02 ( final velocity − inital velocity ) × 0.02 a = 10 0.02 − 6 0.02 ( 10 − 6 ) × 0.02 a = 20.24 metres per second Prac 3: L=length= 30 cm T=period= 15.15 seconds G= G L ¿ ¿ ¿ T = 2 π √ ¿ T 2 π = √ L G T 2 4 π 2 = L G G = 4 π L 2 T G = 4 × π× 30 2 15.15 G = 746.52 ( 2 decimal places )...
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