Let us describe the functorG(i)n,κin detail. First note that forzǫ11⊠· · ·⊠zǫnn∈T(Sn,κ) andǫi=−1 the objectHomA(zi,1)⊗zǫ11⊠· · ·hatwiderzǫii· · ·⊠zǫnn∈T(S(i)n,κ)(C.7)(with the symbolhatwidezindicating that the factorzis to be removed from the expression) comescanonically with the following balancings: Fora∈ Athe balancing betweenzi−1andzi+1is, incase the orientations are as in the picture (C.3),HomA(zi,1)⊗zi−1.a⊠zi+1= HomA(zi,1)⊗(zi−1⊗a)⊠zi+1∼= HomA(zi⊗[κi]a,1)⊗zi−1⊠zi+1∼= HomA(zi,[κi−1]a)⊗zi−1⊠zi+1∼= HomA([κi−2]a⊗zi,1)⊗zi−1⊠zi+1∼= HomA(zi,1)⊗zi−1⊠zi+1.[κi+κi+1]a,(C.8)and similarly for other combinations of orientations. In these expressions we display only therelevant part of the object, and we use the balancings of the objectzǫ11⊠· · ·⊠zǫnnin steps two