Prob7_24soln - 7.24 Two pounds of air initially at 200°F...

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Unformatted text preview: 7.24 Two pounds of air initially at 200°F and 50 lbf/in.2 undergo two processes in series: in Process 1—2: Isothermal to p2 = 101mm} ‘ M aNWWMWEm-“wmww«v«wwwmmww—w~-~~MW»~5» Process 2—3: Constant pressure to T3 = —10°F C Employing the ideal gas model ’ (3) represent each process on a p—v diagram and indicate ‘ the dead state. (b) determine the change in exergy for each process, in Btu. Let To = 77°F, p0 = 14.7lbf/in.2 and ignore the effects of motion and gravity. :Changc m EXZng 9% Closed existewe: \ , H ~ ‘ J ‘ ,jnovffl moi-mu { armli’v] er.{cvsaywa—wwmgafi we «as; E; E. = m (“5%) 1* EWK-W'WCMD “€17,015" Q!“ [MR (:defl 3&5 w/ ox‘thfi)? (,LL 41, (A, jph/m +ai>ie (1‘57ng l>u+ T3111, 56 M1=L¢LL Mame 41‘ 73mm {Watts WW 7f: RT’ mini ’U’L‘ €11 / P PL 5 = M e WWW/'1 fl‘wi’ T‘ T; 50;?»3. Am. = 20¢(T)'A°(Tz> - K 1% {if WW , cw 4mm iFor?mog,§[email protected]—*© an»; fleSame“-bols" a and M3 ) «,3 m4 A3731 ...
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