# sm4_114 - 4.114 Awell-insulated rigid tank of volume 7 ft3...

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Unformatted text preview: 4.114 Awell-insulated rigid tank of volume 7 ft3 initially contains helium at 160°F and 30 lbf/in.2 A valve connected to the tank is opened, and helium is withdrawn slowly until the pressure within the tank drops 41> PL. 2. An electrical resistor inside the tank maintains the temperature at 160°F (a) Determine the mass of helium withdrawn, in lb, and the energy input to the resistor, in Btu, when Pm: \3 (b) Plot the quantities of part (a) versus p ranging from 15 to 30 lbf/in.'2 PROBLEM 4-134“ gnaw”: Heiwm is wi‘ékdrowv‘ siovly rﬁrom « Qw~mgalnl~ld %»k. 3W wle Wm «km pasture with.» What»; 3», "PM ﬁwirakrf w.%~.~a {hawkmk {3 hair}- Cent‘kni b3 «51 chva-wt N31473:)”. 5,3313: it] {whys ‘3‘: (315%)“), dgkrwum M MAS: h; hill’M dmdm (may alan “519 «ﬂu rumor, (1:) P1911 wqwnﬁ’fm ofpuu‘a; W’rms 9 («9‘3th from IFS-{p 30 itrflia} 5: gm “a & 6’95“ BMW: Ewéexnovﬂ: l- W cm 4m voamg, a: O . is slaw“ .‘mwﬁu scywmwht. <2. ﬁrm /// m cah‘hml volthn Qch-0 J, and i *e’ ﬁtneﬁ‘tfpoi‘enhm emergu sj—jrcﬂw ®é£t¢5+ r (’1’ 3“. zfgl'wtex Z . Ndh'vw y; WMQé' new}? 1““186"F I 62: a.» 4 Kim-J? Sax. 4.‘ M mg: w} {NF/‘0 3230‘th 4M Antiviral“ .‘t that emak’w in gamed, m3“ FMA m,a W MA war“ 0.5 l—‘onc ap Pa. A»mvu:: TM mg: a; “(1mm warm—em 'gwa. “hwy: :nurm.qwo rm _ . 4~Htiam bahu¢cn W m;fo «Mod 7 m}; w; +9... We. M M Hausa—w 4M 4‘ WW P7. — \Kfs «wk 046% M...- ‘iwmc: @muaﬁ' w«’+hdarm)n my» Ma. 3...“ 7;: 14.144». am 3» “may”? 3% W1“ W umwﬁvk M M {airmgwma pay—.19; AW : a? * gr h _ I :1;- Caf-irhévm W £73: '- (E! P )RT. ( 3) (.I) - m m »» "‘6’ - L "‘ ‘ MW). e @a-PH42M53) lb {7.) Lara ———> maﬁosow O ' v ’szL ” maul : 1'7/ ’ WV} i? ‘ML '— ﬁkadme MWPW’Wm CafsW-l’ smocT rs WSW'F so “7.: “i , (MZ'MD (1.0+ wow} = — a,“ I (wk-m7) |A (oer ludF) we\a 3 (miymzwﬁw- Wt lQO°F : Me WD’Q/ka-F P5129] VW 7.0m :: me (—- ‘9an / =-w\C RE a = —- .0506 Xbmﬂm mvolwir‘llab) R lB‘l'W = "l’Z,O=aL"Rl>'¥lr < 713N245 : S‘15.53> BM! 4.114 Awell-insulated rigid tank of volume 7 ft3 initially contains helium at 160°F and 30 lbf/in.2 A valve connected to the tank is opened, and helium is withdrawn slowly until the pressure within the tank drops to p. An electrical resistor inside the tank maintains the temperature at 160°F. (a) Determine the mass of helium withdrawn, in lb, and the energy input to the resistor, in Btu, when p=18psi (b) Plot the quantities of part (a) versus p ranging from 15 to 30 lbf/in.2 PROBLEM 4. “4* Known: Helm-m is wi‘lkdrow». slowly “Ham ax ww-rncufakd th03 CW volum urn-kl -Hu. [Manure WIH-aH Wknhq ’0. TM Run-penal“: chum-o1 'fkq‘l‘nk 1'5 Ktp'i- Cow-shat b: an clack-Int Msl‘SfDr‘. Fmbt “l twink ftrﬁl‘h—F/m’, dekruum HM. M4,“ a4 lule corn-de annual-HA. {aura} Input) +9 «flu Ntu'sfbr, Us} Pﬂo‘f +k'ﬁwuh'f'"f “{Pﬂi‘“) VP’FMJ P mnjuns frown f5“ #0 30 Ibfh'mi w GIVEN Dam: ENQQJ’HDDEL.’ I- Thu ecu-\th volume. IIS 5:th IlW‘I'N :c-Pwma—i‘p" '2' RV“ Ctran votoM'J chzo J “*4 Y—meh‘q‘fwfenho-ﬁ enefﬁj ‘5'?th kw. ignore. 2. Haul/mu; Md»! (:1 5,, A” 4 «A Sac. 4—. TM ms: of {*4 Mpﬁgr is that enoka b-l namedﬂ ANALYSIS: TM ms: 01‘ helium wad-fnm awa— +‘Mﬁ (Ah/U11 HUAL 1““ d-Huenu. b4: haunt -{~u. "uh-A «mad 7 M51 withhﬂt H ‘1'“- M‘L‘“ M {div-k F5444. My 'hV-tel @M‘Ud tun-+11%”): Wt-Mz. Sun-4.- 7:: I’LJ ‘Hp'h ' JM j“ "[IJa-ﬁmvs Shetl- wle-L LAM-J. DNWﬂ-ﬁ M ﬁttmjwma PlgP' 3m: L-Y._v__lr.~_(e.—ml u) RT’ In W _1 ( 3) : Lawpﬂ'i’vifﬂ 244:: J strum m it :51 ur'ﬁ- (mm) = (éo-P)(4.2m53) lb 17-3 Th! “‘1 N49 htanu dlM:rlld,f-: aha , Th4 cur}; Am has-«LA...th mm f—o and” = 37:: '6‘“ ““J‘ib‘c- Tnh‘ﬂﬁnj 44'“ M15“ mzt. ‘91.“;an and mh"*§ {'14-‘11 5‘ rem»? cath blah-14.. hA-pnraN—dJ-o Lamina-d") \$3" ‘ ‘ w‘” + he ‘22:" a“? AU‘V = —U-’cv +3“? 0% g 0ch): Mil-l; -h.u’—LW;-W,]lﬂe I Elm “want-Pure L; Quihu'f/ ulzutTJ,u,-.u{1‘)) L19 2 MC?) +Qv)e_ Tu... © Q—UU‘V) =1 {m,-w;1pt.9e' ~37 LuHLfk- {Eb-«(544 31‘).th SMJﬁ'w‘V):£mf'mL)R—[ 3155.0] LM.-|ML\ =(P.-P}V!RTJ ‘J-WMQ ('W‘V) =(Pl-PYV- Tax-“3; (WW): {ho-pjﬂgfgl 'fjﬂ‘fllw‘)|%b¥ 2 1.236(30-9) an (3) (a) (ulna Flown-.3, 5T“) 5mm (M.w1fk¢rm):O-OSOSK315?‘”) 5”" ‘3’“— (-wcu‘): 155\$ RM' (no) PLOTS Pa u—k mkdr‘wn) lb an (“U3”)! EM l5 Pugh-\$1) 3O 15' Pabﬂhg) 30 1. To msnht“ “u. +fw-Pcrg41-er wiﬂuum hat cons-ha} {Wu myth..- Murt farm/rd... can” +0 in. lam-hum w: thk him-l 1'0 +94 4W3? mnl‘rd ad by Hutu- war-r; out {1. ...
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