Unformatted text preview: y = ( x 2 + 1) 2 d dx [ y ( x 2 + 1) 2 ] = x 4 + 2 x 2 + 1 y ( x 2 + 1) 2 = x 5 5 + 2 x 3 3 + x + C y = 1 ( x 2 + 1) 2 ( x 5 5 + 2 x 3 3 + x + C ) Using the initial condition y (0) =2, we have2 = C , so y ( x ) = 1 ( x 2 + 1) 2 ( x 5 5 + 2 x 3 3 + x2) . 1...
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 Spring '07
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 Math, UCLA ID, 2. dx

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