This preview shows page 1. Sign up to view the full content.
Unformatted text preview: f x = ( x1 + x2 y 3 ) and integrating by x , we get f ( x,y ) = log xx1 y 3 + ( y ) . Dierentiating by y , we have f y =3 x1 y 2 + ( y ), which must equal3 x1 y 2 . Hence we must have ( y ) = 0, so we can take ( y ) = 0. The solution to the dierential equation is simply f ( x,y ) = C , so log xx1 y 3 = C. Using the initial condition y (1) = 8, we have8 3 = C , so the solution to the initial value problem is log xx1 y 3 =8 3 . 1...
View
Full
Document
 Spring '07
 staff
 Math

Click to edit the document details