# solutions6ac - Math 33b Quiz 6ac March 4 2008 Name UCLA ID...

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Math 33b, Quiz 6ac, March 4, 2008 Name: UCLA ID: 1. Find the solution, with initial condition ~x (0) = 2 3 , to the system of differential equations d~x dt = - 1 - 1 4 - 5 ~x. Solution. The characteristic equation of the matrix is det( A - λI ) = det - 1 - λ - 1 4 - 5 - λ , which is λ 2 + 6 λ + 9. The roots are λ = - 3 , - 3, so there is only one eigenvalue λ = - 3. We attempt to find eigenvectors for λ = - 3. Solving ( A - ( - 3) I ) ~v = ~ 0, we have 2 - 1 4 - 2 v 1 v 2 = 0 0 . Writing them out as equations, we have 2 v 1 - v 2 = 0 4 v 1 - 2 v 2 = 0 As usual, the two equations are multiples of each other, so we need only find a nonzero solution to 2 v 1 - v 2 = 0. If we choose v 1 = 1, then v 1 = 2 and so ~v = 1 2 . To write down the solution to the system of differential equations, we must find a pseudoeigenvector ~w such that ( A - ( - 3) I ) ~w = ~v . Writing everything out, we want 2 -

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• Spring '07
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• Equations, initial condition

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