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Unformatted text preview: We will divide the graph into 8 divisions with a Δx of 5. (these divisions are marked by dashed lines on the graph). First we can find the area between the curve and the xaxis from x=0 to x=5. The first area is given by a trapezoid so we can divide the area into a rectangle and a triangle. The rectangle portion will be 10*5 which equals 50 and the triangle part will be (1/2)((15(10))*5) which equals 25 so the area of the first trapezoid will be 25. So, at point 5, g(x) will be 5025=25. We will use this same method for the rest of the divisions. For the division at x=10 we have a larger trapezoid. So the rectangle area is (10*10)=100 and the triangle area is (1/2)((20(10))*10)=50 so the total area is 150. So g(10) is 25150=125. …… x 0 5 10 15 20 25 30 35 40 g(x) 50 25 125 Should I keep going with this??? (10,20)10 g’(x) 40 15 (20,10) x...
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 Spring '08
 BLAKELOCK
 Calculus, 50 g, one hour, 5 miles, 0 5 10 15 20 25 g

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