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**Unformatted text preview: **We will divide the graph into 8 divisions with a Δx of 5. (these divisions are marked by dashed lines on the graph). First we can find the area between the curve and the x-axis from x=0 to x=5. The first area is given by a trapezoid so we can divide the area into a rectangle and a triangle. The rectangle portion will be -10*5 which equals -50 and the triangle part will be (1/2)((-15-(-10))*5) which equals -25 so the area of the first trapezoid will be -25. So, at point 5, g(x) will be 50-25=25. We will use this same method for the rest of the divisions. For the division at x=10 we have a larger trapezoid. So the rectangle area is (-10*10)=-100 and the triangle area is (1/2)((-20-(-10))*10)=-50 so the total area is -150. So g(10) is 25-150=-125. …… x 0 5 10 15 20 25 30 35 40 g(x) 50 25 -125 Should I keep going with this??? (10,-20)-10 g’(x) 40 15 (20,10) x...

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- Spring '08
- BLAKELOCK
- Calculus, 50 g, one hour, 5 miles, 0 5 10 15 20 25 g