group Homework 12

# group Homework 12 - Homework 12 5/3#34 We know The cyclist...

• Notes
• 2

This preview shows pages 1–2. Sign up to view the full content.

Homework 12 5/3 #34 We know: The cyclist begins at point 5 miles from the lake. Positive velocities (v(t)) take her away from the lake while negative velocities (-v(t)) take her toward the lake. We can see by the graph that her distance traveled at a positive velocity is much greater than her distance traveled at a negative velocity. (Because the area between the curve and the axis is much greater for when the graph of her velocity is positive than when the graph of her velocities is negative.) Therefore, her net displacement will be in the positive direction (away from the lake). She will be the farthest away from the lake at the END of her trip because her net displacement is positive (this occurs at t=1, one hour). Now we need to find how far she is from her starting point: We will divide the graph into 6 subintervals so n=6 and Δt=(1/6). = - = - - - = - = 6 1 1 6 1 1 1 ) )( ( ) )( ( n n n n n n n n t t t v um RightHandS t t t v m LeftHandSu 6/1 #18. We know: g(0)=50 g’ is graphed below: Using this graph we can form a chart for g(x).

This preview has intentionally blurred sections. Sign up to view the full version.

This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: We will divide the graph into 8 divisions with a Δx of 5. (these divisions are marked by dashed lines on the graph). First we can find the area between the curve and the x-axis from x=0 to x=5. The first area is given by a trapezoid so we can divide the area into a rectangle and a triangle. The rectangle portion will be -10*5 which equals -50 and the triangle part will be (1/2)((-15-(-10))*5) which equals -25 so the area of the first trapezoid will be -25. So, at point 5, g(x) will be 50-25=25. We will use this same method for the rest of the divisions. For the division at x=10 we have a larger trapezoid. So the rectangle area is (-10*10)=-100 and the triangle area is (1/2)((-20-(-10))*10)=-50 so the total area is -150. So g(10) is 25-150=-125. …… x 0 5 10 15 20 25 30 35 40 g(x) 50 25 -125 Should I keep going with this??? (10,-20)-10 g’(x) 40 15 (20,10) x...
View Full Document

• Spring '08
• BLAKELOCK
• Calculus, 50 g, one hour, 5 miles, 0 5 10 15 20 25 g

{[ snackBarMessage ]}

### What students are saying

• As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

Kiran Temple University Fox School of Business ‘17, Course Hero Intern

• I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

Dana University of Pennsylvania ‘17, Course Hero Intern

• The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

Jill Tulane University ‘16, Course Hero Intern