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**Unformatted text preview: **Then we must find the positive areas above the x-axis. Again, we must use the area formulas for a triangle for Area 4 and Area 8 and a trapezoid for Area 5, 6, and 7. A 4 =(1/2)(5)(10) = 25 *Again note that these area values are now positive because above the x-axis A 5 =(1/2)(5)(10+7.5)=43.75 A 6 =(1/2)(5)(7.5+5)= 31.25 A 7 =(1/2)(5)(5+2.5)=18.75 A 8 =(1/2)(5)(2.5)= 6.25 Now, from knowing these areas, we can find the true value of g(x) at the different x-values in increments of 5. In order to find the exact position, we take our known value, g(0)=50 and add the areas that we have found. We did this, and our g(x) values can be found in the table below. x 0 5 10 15 20 25 30 35 40 g(x) 50 -12.5 -100 -150 -125 -81.25 -50 -31.25 -25 Therefore, from plotting these values, our graph of g(x), with critical points at x=15 and x=40, as well as inflection points at x=10 and x=20, looks like: (10,-20)-10 g’(x) 40 15 (20,10) x...

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- Spring '08
- BLAKELOCK
- Math, Calculus, Division, Critical Point, 50 g, Heron's formula, 0 5 10 15 20 25 30 35 40 g