MOSFET-practice-solns

# MOSFET-practice-solns - Solution to the practice problems 1...

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Solution to the practice problems 1. V DD A B A B C C Out Out = (AB+C)’ 2. Draw a CMOS circuit for the function: Out = (AB)’ +A’C Out = (AB)’ V DD A B A B Out 3.Analyze the flooolwing NMOS circuit. K = 1mA/V 2 and V to = 1V

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4 a) Small signal equivalent circuit: Open circuit voltage gain: Output resistance R o1 : Add a test voltage source and take out v i . The dependent current source becomes only dependent on the test voltage source. That means we can regard it as a resistor with resistance of 1/g m . b) Small signal equivalent circuit: Input resistance R in : 51 50 ) 10 )( ( ) 10 )( ( 1 1 1 = ! " = ! = i o o i m gs m o v v k v v g k v g v g m v gs G S D V i 10k V o1 ! = + ! ! = 196 / 1 10 ) / 1 )( 10 ( 1 m m o g k g k R ! = ! " + = ! + = = 196 ) 10 ))( ( ( ) 10 )( ( 2 2 i i m i i gs m i i i in i k v g i i k v g i i v R g m v gs G S D V i2 10k V o 5k 2k v gs i i

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Voltage gain: c) For this cascaded circuit, because voltage-gain depends on the load resistance, the gain for the first stage needs to be modified. The load resistance of the first stage would be the input resistance of the second stage, which is 196 .
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