# Lab 7.docx - Sumner 1 Alyssa Sumner Paul Buckley Chem 106...

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Sumner 1 Alyssa Sumner Paul Buckley Chem 106 Lab 13 October 2019 Titration of an Acid (1) 0 2 4 6 8 10 12 14 0 2 4 6 8 10 12 Titration of an Acid mL pH (2) pH mL added 1.94 0 1.98 0.5 2.01 1 2.06 1.5 2.12 2 2.19 2.5 2.27 3 2.35 3.5 2.47 4 2.58 4.5 2.77 5 3.05 5.5 3.88 6 4.87 6.5 5.3 7 5.53 7.5 5.64 7.78 5.7 8
Sumner 2 5.78 8.2 5.83 8.4 5.98 8.9 6.12 9.4 6.24 9.9 6.41 10.4 6.5 10.68 6.56 10.88 6.66 11.18 6.77 11.4 7.17 11.9 7.48 12.1 7.77 12.38 10.6 12.52 11.31 12.98 (3) To find our pKa we must find were our graph flattens out or our half equivalence point, in this case this is at 3.88 and 10.6. To find our Ka from this we must do 10 pKa , therefore our Ka values are 1.32* 10 4 and 2.51* 10 11 . Our equivalence points are 2.19 and 6.12. (4) The pKa values I found were 1.92 and 6.33 Source: Gilbert, Kiress, Foster, and Davies. Chemistry Third Edition. New York. W.W Norton and company, 2012. Print. Percent difference of pKa one: 3.88 ( 3.88 + 1.92 ) 100 = 66.9% Percent difference of pKa two: 10.6 ( 10.6 + 6.33 ) 100 = 62.6% Summery: Write a brief summary of your experiment. As part of this, you have to describe: a) What you were trying to accomplish b) What your experimental approach was (or how you did it) c) What your results were.

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