Unformatted text preview: ME 467
19. Your company has been casting an old metal product for years; you know from experience
that it solidifies in 10 minutes.
You now need to estimate a new product's cooling time, given that it is made from the exact
same material and is poured at the exact same temperature.
But, the new part has a different geometry.
Given below the respective volumes and areas for the parts of interest, estimate the cooling
(solidification) time for the new part design. Give answer in minutes.
VOLD = 90,000. mm3
AOLD = 17,000. mm2
VNEW = 45,000. mm3
ANEW = 34,000. mm2
Show your work
T = Co
Realize : Can, = Cuz ( same material )
V2 = /2VI . Az= 2A ,
or: V. = 2 V2
Com = T. ( V ) = T2 ( V 2 ) = Tz ( 72VI )
7 2 = T ( A( ) 2 / KK| 2
= T ( # ) = ( 10 min ) ( 1/6 )
72 = 0, 625 min
( If Can calculated, Can= TI (#! ) ? = 1 10 mins( take me ) = 0135 Themed )
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- Summer '19