E7E906FB-5B5E-46E1-80C3-0307F84B0F12.jpeg - Physics 1A Solution 3 November 1 2019 b We can write the force balance FNet = m x a in each component for

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Unformatted text preview: Physics 1A Solution 3 November 1, 2019 b) We can write the force balance FNet = m x a in each component for each box: Box A &amp; : T = MAXa Box A y : -mag + FN = MAX0 Box By : T - mBg = mB X (-a) where in the last equation we have used the fact that Box A moves left with the same acceleration as Box Solving we get: B moving downward. We can use the expression for T = mAd in the first equation and plug into the third. MAa - mBg = -mBa a(mAtmB) = mBg a = MBg MATMB From here we can again use T = mAa to find T = - mAmBg MA + MB c) We can plug in to the expression for a that we found: a = a= - mBg 5 kg 10 m/s mAtmB 13 kg + 5 kg = 2.8 m/s2 30 .. MacBook Pro C Q Search or type URL + # % &amp; 5 6 7 8 9 E R T Y U O P D F G H K C V N M...
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