CD2D9CB7-2B90-45FE-9876-04A3311EBD73.jpeg - Down Page 2 of 3 z mg = kx my 0.116m c = k Problem 5 Rollercoaster a At each point we know that all of the

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Unformatted text preview: Down Page 2 of 3 - z mg = kx my _ 0.116m c = k Problem 5: Rollercoaster a) At each point, we know that all of the potential energy from the change in height, gets converted to kinetic energy, so we have mgAh = mv2/2 - v = v(2gAh). We can use this formula to find the speed at points 2, 3 and 4: Ah = 32m - v = \2 x 10m/s x 32m = 25.3m/s Ah = 32 - 26m = 6m - v = \2 x 10m/s2 x 6m = 11.0m/s Ah = 32 - 14m = 18m - v = \2 x 10m/s' x 18m = 19.0m/s b) For this we need to use the full conservation of energy: W = APE + AKE -Fid = mgAh+&quot; mv? -0.23migd = mgAh + m f 2 v} = v? - 2g(Ah + 0.23d) = (1.3m/s)2 - 2 x 10m/s2(-32m + 0.23 x 45m) = 434.69m?/s2 uf = 20.84m/s 30 ... MacBook Pro C Q Search or type URL + % 4 5 O E R T Y U O P D F G H K...
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• Fall '13
• JeffreyHutchinson

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