Workshop Tutorials for Technological and Applied Physics 5.docx - Workshop Tutorials for Technological and Applied Physics Solutions to ER5T Capacitance

Workshop Tutorials for Technological and Applied Physics 5.docx

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Workshop Tutorials for Technological and Applied Physics Solutions to ER5T: Capacitance Questions: a. Capacitance of a parallel plate capacitor. a. Since C = ε 0 A ,reducing d to half its value will double the capacitance. d b. Doubling the area of both plates will again double the capacitance (assuming an ideal capacitor). c. Doubling the area of one plate only will not change the capacitance since A is the area of overlap. d. If the area of overlap is 50% of its original value, then the capacitance also halves. e. Doubling the potential difference between the plates results in no change in the capacitance. The capacitance is determined by geometrical quantities. b. Charge, capacitance and potential difference. a. See diagram opposite. b. The slope of the graph is the capacitance, C = Q/V . The unit CV -1 is also called the farad, in honour of Michael Faraday who did a lot of the early work in electromagnetism. c. See diagram opposite. The area under the curve, shaded grey, is a triangle and has area _ base × height = _ V 0 × Q oi = _ V 0 ( V 0 × C ) = _ V 0 2 C which is the energy stored in the capacitor.
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