Stahl, Boyle's Law Post Lab - Ashlynn Stahl Chem Lab...

This preview shows page 1 - 2 out of 2 pages.

Ashlynn Stahl Chem. Lab 10/22/19 Boyle’s Law Post Lab 1) Calculate the number of moles of gas in the syringe using data from the graph. There was 4.8x10 -4 . moles of gas in the syringe. 2) Calculate the number of molecules of gas in the syringe using Avagadro’s number and the number of moles you calculated earlier. (Avagadro’s number = 6.02 x 10 23 molecules/mol). 2.9 x 10 20 molecules/mol. How many of those molecules are oxygen? (research the percent of O 2 in the atmosphere and calculate using ratios). x= .21(2.9 x 10 20 molecules/mole) 6.09 X 10 19 of those molecules are oxygen. Calculate the volume for 1 mole using your answer from postlab question 1. Calculate your percent error compared to the standard value for the volume of one mole of gas at STP - 22.4L. (Hint: ) The volume of one mole is 2.08 x 10 -7 . The % error is 2.08 x 10 7 / 22.4 ( 100 )= 1.95% What happens to the molecules in the gas when compressed? What would happen to
Image of page 1
Image of page 2

You've reached the end of your free preview.

Want to read both pages?

Unformatted text preview: them if you continued to compress the molecules (if you had infinite strength)? Assume the syringe doesn't explode - just focus on what happens to the molecules. When the gas in the syringe is compressed the molecules bounce off the edges of the container more frequently and the presser becomes higher. If the gas was continued being compressed the molecules would be condensed and condensed until it turns into a liquid form. show your data below Table 1 Pressure (kPa) Volume (mL) Pressure (kPa) constant, k 5.8 189.20 1097.36 7.8 146.75 1144.65 9.8 115.86 1135.428 11.8 96.55 1139.29 13.8 80.91 1116.558 15.8 70.10 1107.58 17.8 62.73 1116.594 19.8 57.10 1130.58 Average K 1123.505k k value from graph 2 1173kPa/L/mL *************** % error 4.219% *************** T in K: 295.15K Calculate the number of moles in your syringe (SHOW ALL WORK) n = 4.8 x 10-4...
View Full Document

  • Fall '19

What students are saying

  • Left Quote Icon

    As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

    Student Picture

    Kiran Temple University Fox School of Business ‘17, Course Hero Intern

  • Left Quote Icon

    I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

    Student Picture

    Dana University of Pennsylvania ‘17, Course Hero Intern

  • Left Quote Icon

    The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

    Student Picture

    Jill Tulane University ‘16, Course Hero Intern

Stuck? We have tutors online 24/7 who can help you get unstuck.
A+ icon
Ask Expert Tutors You can ask You can ask ( soon) You can ask (will expire )
Answers in as fast as 15 minutes
A+ icon
Ask Expert Tutors