mat4.docx - Pembahasan Maka luas segi dua belas di atas adalah L = 12 x ½ x 144 x sin 30 L = 12 x 72 x ½ L = 6 x 72 L = 432 cm2 Jawaban d 1 Jika besar

mat4.docx - Pembahasan Maka luas segi dua belas di atas...

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Pembahasan: Maka luas segi dua belas di atas adalah: L = 12 x ½ x 144 x sin 30 L = 12 x 72 x ½ L = 6 x 72 L = 432 cm 2 Jawaban: d 1. Jika besar sudut dalam segi-8 beraturan adalah x maka sin x + cos x = ... a. 0 b. ½ √2 c. – √2 d. √2 e. ¼ √2 Pembahasan: < AOB = 360/8 = 45 <ABO = (180 – 45) : 2 = 67,5 Sudut segi-8 atau <ABC = <ABO +<OBC = 67,5 x 2 = 135 Maka nilai dari sin x + cos x = sin 135 + cos 135 = sin (180 + 45) + (-cos (180 + 45)
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Unformatted text preview: = sin 45 + (-cos 45) = ½ √2 - ½ √2 = 0 Jawaban: a 2. Jika 0 ≤ x ≤ 2π dan 0 ≤ y ≤ 2π memenuhi persamaan sin (y + x) = sin y . cos x maka cos y . sin x = ... a.-1 b. – ½ c. d. ½ e. 1 Pembahasan: Sin (y + x) = sin y . cos x + cosy . sin x sin y . cos x = sin y . cos x + cosy . sin x cosy . sin x = sin y . cos x - sin y . cos x cosy . sin x = 0 Jawaban: c...
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