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**Unformatted text preview: **∂f ∂h = 2 t 2 ∂f ∂t =-4h t 3 t ̃ = t ± Δt (t=11.65, Δt = 0.01) h ෨ ൌhേΔh (h=660, Δh = 0.01) g ൌgേΔg Applying propagation of error concept using first order approximation, Δg= ฬ ∂f ∂t Δt ฬ + ฬ ∂f ∂h Δh ฬ Δg= 1.67*0.01 0.0147*0.01 (considering infinite precision for intermediate calculations) (3 marks) = 0.0168 ൎ 0.02 (2 marks) gേΔg ൎ 9.73 േ 0.02 m/s 2 (1+1 marks)...

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- Fall '19