prelabstatic (1).doc - Pre-Lab Static Equilibrium Name This is part D of your lab The weight(F2 on the right is unknown This system is in static

prelabstatic (1).doc - Pre-Lab Static Equilibrium Name This...

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Pre-Lab: Static Equilibrium Name: This is part D of your lab. The weight (F 2 ) on the right is unknown. This system is in static equilibrium. Example: Torque exerted by F 1 1. τ = F d (d = pivot point to point of attachment) 2. τ = (sin 60º 6 N) 0.3m (d = 50 cm - 20 cm = 0.3 m) 3. τ = 1.56 Nm in the clockwise (cw) direction The lab manual simplifies Torque as being the perpendicular component of force multiplied by the distance to pivot point. Why cw? If you pull up on the meter stick at 20 cm while it rotates about the 50 cm mark, the stick will rotate cw. 1. (½) Do both the forces and torques sum to zero when in static equilibrium? a. No b. Yes c. Depends on the chosen pivot point 2. (1) What is the value of F 2 ? 3. (½) What is the F net ? (select all that apply) a. 4.8 + 1.0 + 2.4 + cos 60°(6) + cos 45°(F 2 ) = 0 b. 4.8 + 1.0 + 2.4 - cos 60°(6) - cos
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