{[ promptMessage ]}

Bookmark it

{[ promptMessage ]}

W8_thermo_key

# W8_thermo_key - 2 NOCl(g ∆ G° =-40.9 kJ mole-1 ∆ H°...

This preview shows page 1. Sign up to view the full content.

Chem 125 Dr. Retsek Winter 2008 Worksheet 8: Thermo 1. For the reaction, (CH 3 ) 2 CHOH (g) (CH 3 ) 2 CO (g) + H 2 the equilibrium constant is 0.444 at 452 K. Is this reaction product-favored or reactant-favored under standard conditions? Will the reaction be spontaneous when the partial pressures are (from left to right in the reaction), 1.0, 0.1, and 0.1 atm? reactant-favored ( G° > 0); spontaneous ( G < 0) 2. At what temperature will the equilibrium constant for the formation of NOCl (g) be equal to 1.00 x 10 3 ? Data for this reaction at 25°C are: 2 NO (g) + Cl 2 (g)
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: 2 NOCl (g) ∆ G° = -40.9 kJ mole-1 ∆ H° = -77.1 kJ mole-1 ∆ S° = -121.3 J mole-1 k-1 (You can assume that ∆ H° and ∆ S° do not change much with temperature, but ∆ G° will.) T = 431 K 3. Using the information in question #2, what is the value for the equilibrium constant at 25°C? K = 1.5 x 10 7 at 75°C? K 2 = 1.7 x 10 5 4. At 298 K, ∆ G f °[CO(g)] = -137.2 kJ mole-1 and K p = 6.5 x 10 11 for the reaction CO (g) + Cl 2 (g) ⇄ COCl 2 (g). Use these data to determine ∆ G f °[COCl 2 (g)]. ∆ G f °(COCl 2 ) = -205 kJ/mole...
View Full Document

{[ snackBarMessage ]}

Ask a homework question - tutors are online