# 20190930_110001.jpg - 3.19 ment hi has been compacted in an...

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Unformatted text preview: # 3.19 ment hi has been compacted in an embark. buck density of 2:15 9mice and 1 is 121 . , Gs is 9. 65. Calculate dry density void ratio content would deque of saturation and air impact above possible to dry density soil at 200 9/ m/ cc. W of 13. 5 % to a liven data : 76 : 2.15 9 m / CC = 9150 k9 / m' W = 12'1. = 0.12 Cs = 2.65 998 k91m' find : Yd = ? S = ? e = ? A = > lution : Yd . Gs .Yw - 1 = (2 65) (998 ) - 1 1920 e= 0. 38 ie, void ratio - (0.12) (2 65) 0 . 38 3 = 0 8 37 - 83 7% degree of salvation (s ) Yd = Gs You ( 1 - A ) - 1- (1980 ) ( 1+ (019) (2 65) ) ( 2:65) 1998)...
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