ch10 concept check.pdf - Giselle Godt BSC 2010 Ch 10 Concept Check 10.1.1 CO2 enters the leaves via stomata and water enters the plant via roots and is

ch10 concept check.pdf - Giselle Godt BSC 2010 Ch 10...

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Giselle Godt BSC 2010 Ch 10 Concept Check 10.1.1. CO2 enters the leaves via stomata, and water enters the plant via roots and is carried to the leaves through veins. 10.1.2. Oxygen produced during photosynthesis originates in water, not in carbon dioxide. 10.1.3. The light reactions could not keep producing NADPH and ATP w/out the NADP+, ADP, and phosphate that the Calvin cycle generates. The two cycles are interdependent. 10.2.1. Green, because green light is mostly transmitted and reflected-not absorbed-by photosynthetic pigments. 10.2.2. Water is it initial electron donor; NADP+ accepts electrons at the end of the ETC, becoming reduced to NADPH. 10.2.3. In this experiment, the rate of ATP synthesis would slow and eventually stop. Because the added compound would not allow a proton gradient to build up across the membrane, ATP synthase could not catalyze ATP production. 10.3.1. 6; 18; 12 10.3.2. The more potential energy a molecule stores, the more energy and reducing power is required for the formation of that molecule. Glucose is a valuable energy source because it is
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Unformatted text preview: highly reduced, storing lots of potential energy in its electrons. To reduce CO2 to glucose, much energy and reducing power are required int he form of large numbers of ATP and NADPH molecules, respectively. 10.3.3. The light reactions require ADP and NADP+, which would not be formed in sufficient quantities from ATP and NADPH if the Calvin cycle stopped. 10.3.5. In glycolysis, G3P acts as an intermediate because it is the substrate for the next enzyme and is constantly removed, pulling the reaction equilibrium in the direction of conversion of DHAP to more G3P. In the Calvin Cycle, G3P acts as both an intermediate and a product: for every 3 CO2 molecules that enter the cycle, six G3P are formed, five of which must remain in the cycle and become rearranged to regenerate RuBP molecules. 10.4.2. Without PS I I, no O2 is generated in bundle sheath cells. This avoids the problem of O2 competing with CO2 for binding to RuBisCO in the cells....
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