Centripetal Force Post Lab.docx - Wynn Dixon PHYS 1240-020 Post Lab Centripetal Force 2 1 2 v x =2 m1 r r 2 2 v x =2 r r 2 v =x2 2 2v x= \u221a 2 m1 The

Centripetal Force Post Lab.docx - Wynn Dixon PHYS 1240-020...

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Wynn Dixon PHYS 1240-020 Post Lab Centripetal Force 1. m 1 v 2 r = 2 m 1 x 2 r v r 2 = 2 x r 2 v 2 2 = x 2 x = 2 v 2 The velocity at which the centripetal force would balance the spring force would be multiplied by 2 2 . 2. v = rg v = 80 m 9.8 m s 2 v = 28 m s 28 m s 3.28 ft 1 m 1 mi 5280 ft 3600 s 1 hr = 62.6 mi hr 3. v = rg v = ( 6.37 10 6 m ) 9.8 m s 2 v = 62426000

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Unformatted text preview: m s 62426000 m s ∗ 3.28 ft 1 m ∗ 1 mi 5280 ft ∗ 3600 s 1 hr = 139607236.4 mi hr 4. v = 62426000 m s r = 6.37 ∗ 10 6 m a c = v 2 r a c = ( 62426000 m s ) 2 6.37 ∗ 10 6 m a c = 611774800 m s 2...
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