math 1160 5.5 & 5.6

math 1160 5.5 & 5.6 - Math 1 16 Lecture — Homework...

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Unformatted text preview: Math 1 16 Lecture — Homework #12 Answer Key (Due Thursday, March 18, and Tuesday, March 23, 2004) Section 5.5 2. 5 4. 120 6. 66 8. 20 18- 151,200 20. 5040 22. P(6,2) = 30 ways 24. C(5,3) = 10 pizzas 26. P(6,6) = 720 ways 28. C(10,4) = 210 ways 34. C(85) = 56 ways 36. C(10.5) = 252 ways 47. C(52,5) = 2,598,960 hands 48. C(85) = 56 hands 49{ C(13,5) = 1287 hands 50. C(26,5) = 65,780 hands 54.‘ P(6,3) = 120 signals 66. C(20,3) F. C(14,2) = 103,740 Ways ‘y'uu uric‘x‘l i \IHL'CI\ ANNI) l A'illl'lt'ililiiiifx MI) {Insiilyij 68. C(7,3)=35 ways 77a. C(45,5) = 1,221,759 tickets 77b- C(100,4) = 3,921,225 tickets 77c. First lottery 77d. Second lottery r. Section 5.6 43. C(12,4)== 495 4b. C(8,4) = 70 4c. C(82) x C(4,2) = 168 Multiply because both must be me (2 red balls AND 2 white balls) 4d. C(33) x C(4,1) + C(8,4) x C(4,0) = 294 Add hrs—gums: mu nun gt! 3 red imiix/i mm imii ("JR ‘i rmi huiix/‘ii whim huiix m mes: tin? criteria 1' 9 \ { Jii‘xi-ifi. 4e. C(8,4) x C(4,0) » C(83) x C(4,1) C(8,1) x C(43) C(81)) x C(4,4) = 327 (4 red and 0 white) or (3 red and l whim) or (1 red and 3 White) or (0 red and 4 white) 6a. 2x2x2x2x2x2x2x2=256 (or28) 6b. C(83) = 56 6c. C(82) + C(83) + C(8,4) + C(85) + C(8,6) + C(8,7) + C(8,8) = 247 OR 28 — C(8,0) — C(8,l) **This is total outcomes minus those not meeting criteria 6d, C(8,4) + C(85) = 126 ...
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This note was uploaded on 04/02/2008 for the course MATH 1160 taught by Professor Hernandez during the Fall '05 term at Western Michigan.

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math 1160 5.5 & 5.6 - Math 1 16 Lecture — Homework...

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