1113 - More practice with molarity: 3 2 3 2 3 2 3 2 (0.220...

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More practice with molarity: How many grams of Ca(NO ) would it take to make 175 mL of a 0.220 M solution? What is the [NO 3 1- ] in this solution? How many moles NO 3 1- are present in this solution? (0.440 mol NO 3 1- )(0.175 L) = 0.077 mol NO 3 1 - (L solution) Ca(NO 3 ) 2 Ca 2+ + 2 NO 3 1- [NO 3 1- ] = 2 [Ca(NO 3 ) 2 ] = 0.440 M (0.220 mol Ca(NO 3 ) 2 )(0.175 L)(164 g Ca(NO 3 ) 2 ) = 6.31 g Ca(NO 3 ) 2 (L solution) (mol Ca(NO 3 ) 2 ) What is the total concentration of all ions present in this solution? Ca(NO 3 ) 2 1 Ca 2+ + 2 NO 3 1- 3 ions are formed [ion] total = 3 [Ca(NO 3 ) 2 ] = 3 (0.220 M) = 0.660 M
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A little review from Chapter 9: If K is 3x10 and you begin with 3 moles of C and 5 moles R = k [O ] Carbon! It all gets used up. Really measured experimentally!
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Section 10.1 Density Density (d) - a measure of the mass per unit volume of a substance. d water = 1 g/mL 1 mL of water weighs 1 g! d lead = 11.3 g/mL 1 mL of lead weighs 11.3 g! So, most dense to least dense: lead >> carbon >> water Dense substances sink to the bottom of a mixture: increasing density Pb C H 2 O
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Section 10.2 Solvation For the reaction : A(s) A(aq) H solution Enthalpy of solution- heat needed or released when something is dissolved. A substance is soluble if solution or solution is negative.
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Section 10.2 Solvation When this maximum amount of solute has been dissolved, the solution is “ saturated ”. Solubility - the maximum amount of solute that can be dissolved in a volume of solvent at a given temperature. Solubility Classification > 0.1 M soluble between 0.1 and 0.01 M moderately soluble < 0.01 M insoluble If a substance won’t dissolve in a solvent, it is “ insoluble ”.
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Section 10.2 Solvation If two substances (usually liquids) are soluble in each
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This note was uploaded on 06/14/2009 for the course CH 101 taught by Professor Bigham during the Spring '08 term at N.C. State.

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1113 - More practice with molarity: 3 2 3 2 3 2 3 2 (0.220...

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