1615 which expresses kp in terms of the number of

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Unformatted text preview: than the others. For example, Eq. 1615 is best suited for determining the equilibrium composition of a reacting ideal-gas mixture at a specified temperature and pressure. On the basis of these relations, we may draw the following conclusions about the equilibrium constant KP of ideal-gas mixtures: 1. The KP of a reaction depends on temperature only. It is independent of the pressure of the equilibrium mixture and is not affected by the presence of inert gases. This is because KP depends on G*(T), which depends on 800 | Thermodynamics temperature only, and the G*(T) of inert gases is zero (see Eq. 1614). Thus, at a specified temperature the following four reactions have the same KP value: H2 H2 H2 H2 1 2 O2 1 2 O2 1 2 O2 H 2O H 2O H 2O H 2O 3N2 1.5O2 5N2 at 1 atm at 5 atm at 3 atm at 2 atm 3N2 5N2 2O2 T, K 1000 2000 3000 4000 5000 6000 H2 2H P = 1 atm KP 5.17 1018 2.65 106 0.025 2.545 41.47 267.7 2. The KP of the reverse reaction is 1/KP. This is easily seen from Eq. 1613. For reverse reactions, the products and reactants sw...
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This note was uploaded on 06/15/2009 for the course MAE 3311 taught by Professor Hajisheik during the Summer '08 term at UT Arlington.

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