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Unformatted text preview:  b   c  sin θ 2 = √ 10 √ 5 r 1 − 1 / 50 2 = √ 49 2 = 7 / 2 . Remark : You may have chosen di²erent sides o± the triangle, di²erent directions on the sides, or di²erent order in the cross product. Nevertheless, you should get the same area and, to within sign, the same cross or dot product. 4. The equation is a 2 , − 1 , 1 A·a x, y, z A = a 2 , − 1 , 1 A·a 1 , 2 , 1 A and so we have 2 x − y + z = 1. 5. We can use the ±ormula  ax + by + cz + d  a a, b, c A to obtain  3 ∗ 1 + 2 ∗ 2 + 1 ∗ ( − 3) − 2  r 1 2 + 2 2 + ( − 3) 2 = 2 √ 14 ....
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This note was uploaded on 06/17/2009 for the course MATH 3412341 taught by Professor Staff during the Fall '06 term at UCSD.
 Fall '06
 staff
 Calculus, Vectors, Scalar

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