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# Assign1-1 - Problem Statement 50 The water in a tank is...

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Problem Statement: 50 The water in a tank is pressurized by air, and the pressure is measured by a mulitfluid manometer as shown below. Determine the gage pressure of air in the tank if: 0.20 m 0.30 m 0.46 m Schematic: Assumptions/Approximations: 101.33 kPa Physical Laws: [Equation 1-15] Properties/Sources: 1000.00 Conversions: 850.00 1 N = 1.00 13600.00 1 kPa = 1000.00 g = 9.81 Calculations: In the diagram above for absolute pressure, Check units: h 1 = h 2 = h 3 = P ATM = P = ρ *g*h P GAGE = P ABS - P ATM ρ H2O = kg/m 3 ρ OIL = kg/m 3 kg*m/s 2 ρ Hg = kg/m 3 N/m 2 m/s 2

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158.215 kPa 56.89 kPa Reasoning/Verification/Discussion: By using Pascal's Law and the sum of Forces rule from statics, you could determine the answer using each reference point as a place to sum forces. We will learn that "Forcing Functions" are required for any P ATM = P 1 + ρ H2O *g*h 1 + ρ OIL *g*h 2 - ρ Hg *g*h 3 (kg/m 3 )*(m/s 2 )*(m) = kg/(m*s 2 ) = kg*m/(m 2 *s 2 ) = N/m 2 P 1 = P ATM - ρ H2O *g*h 1 - ρ OIL *g*h 2 + ρ Hg *g*h 3 = [Note that ρ *g*h is divided by 1000 for units] P 1GAGE = P 1 - P ATM = change in energy state such as P or T.
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