Chapter 11 Solutions

# Chapter 11 Solutions - Chapter 11 Solutions 11.1 Ways of...

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Chapter 11 Solutions 11.1 Ways of Expressing Concentration 11.2 Vapor Pressure of a solution 11.3 Boiling-Point Elevation and Freezing-Point Depression 11.4 Osmosis 11.5 Colligative Properties of Ionic Solutions

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11.1 Ways of Expressing Concentration A. Molar Concentration (Molarity, M) 3 - 3 1 - moldm , dm mol , molL , L mol solution of liters solute of moles ) Molarity(M =
B. Molality 1 - molkg , kg mol solvent of kilograms solute of mol molality =

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C. Mass Percentage of Solute 10% w/w NaOH =10 g of NaOH dissolved in 100 g of solution =10 g of NaOH dissolved in 90 g of solvent (water) D. Mole Fraction 100% solution of mass solute of mass Solute of Percentage Mass × = solution of moles total A substance of moles X A =
Exercise: 1. A solution containing 121.8 g of Zn(NO 3 ) 2 per litre has a density of 1.107 g/mL. Calculate its molal concentration. [Ar Zn=65; N=14; O=16] 1. How many grams of NaOH and water are needed to prepare 250.0 g of 1.00% NaOH solution? 1. A mixture containing benzene and toluene has 18.4 g of toluene and its percentage composition is 30%. Calculate the number of moles of benzene in this solution. [Mr benzene = 78 and toluene = 92]

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Colligative properties are properties that depend only on the number of solute particles in solution and not on the nature of the solute particles. Vapor-Pressure Lowering
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## This note was uploaded on 06/21/2009 for the course CHEM 130 taught by Professor Kia during the Spring '09 term at Abraham Baldwin Agricultural College.

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Chapter 11 Solutions - Chapter 11 Solutions 11.1 Ways of...

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