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Unformatted text preview: Volume at equivalence point (mL) : 28.60 mL pH at equivalence point: pH 8 Volume at halfway point (mL) : 14.30 mL pH at halfway point : pH 4.2 pK a : 4.2 pK a = 4.2-log K a = 4.2 K a = 10-4.2 = 6.31 ×10-5 (benzoic acid) Concentration of unknown monoprotic Acid Volume of unknown acid: 25.00 mL Average molarity of NaOH (part A) : Based on your own result Volume of NaOH at equavalance point (ml): 28.60 mL Mol of NaOH = Mol of unknown monoprotic acid M NaOH V NaOH = M unknown acid V unknown acid...
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- Spring '09
- ml, unknown monoprotic acid