RCW3 solutions

# RCW3 solutions - Recitation ClassWork 3 solutions 1 Chapter...

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Recitation ClassWork 3 solutions Physics 203 1. Chapter 4 Problem 4 REASONING According to Newton’s second law, Equation 4.1, the average net force F Σ is equal to the product of the object’s mass m and the average acceleration a . The average acceleration is equal to the change in velocity divided by the elapsed time (Equation 2.4), where the change in velocity is the final velocity v minus the initial velocity v 0 . SOLUTION The average net force exerted on the car and riders is ( ) 0 0 45 m/s 0 m/s 34 5.5 10 kg 3.5 10 N 7.0 s vv F ma m tt = = = ×= × 2. Problem 14 REASONING The acceleration of the sky diver can be obtained directly from Newton’s second law as the net force divided by the sky diver’s mass. The net force is the vector sum of the sky diver’s weight and the drag force. SOLUTION From Newton’s second law, (Equation 4.1), the sky diver’s acceleration is F a m Σ = The free-body diagram shows the two forces acting on the sky diver, his weight W and the drag force f . The net force is F fW Σ= − . Thus, the acceleration can be written as fW a m = The acceleration of the sky diver is 2 1027 N 915 N 1.20 m/s 93.4 kg a m −− = = = +

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## This note was uploaded on 06/22/2009 for the course PHYS 1101 taught by Professor Richardson, b during the Fall '08 term at Cornell.

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RCW3 solutions - Recitation ClassWork 3 solutions 1 Chapter...

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