HW6 solutions

HW6 solutions - HomeWork 6 solutions 1. Chapter 7 problem 6...

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HomeWork 6 solutions Physics 203 1. Chapter 7 problem 6 REASONING During the collision, the bat exerts an impulse on the ball. The impulse is the product of the average force that the bat exerts and the time of contact. According to the impulse-momentum theorem, the impulse is also equal to the change in the momentum of the ball. We will use these two relations to determine the average force exerted by the bat on the ball. SOLUTION The impulse J is given by Equation 7.1 as J = t F , where F is the average force that the bat exerts on the ball and t is the time of contact. According to the impulse-momentum theorem, Equation 7.4, the net average impulse ( ) t Σ∆ F is equal to the change in the ball’s momentum; ( ) tm m Σ ∆= f0 F vv . Since we are ignoring the weight of the ball, the bat’s force is the net force, so Σ= FF . Substituting this value for the net average force into the impulse-momentum equation and solving for the average force gives ( )( ) ( )( ) 3 0.149 kg 45.6 m/s 0.149 kg 40.2 m/s 11 600 N 1.10 10 s mm t −− + = = = ∆× F where the positive direction for the velocity has been chosen as the direction of the incoming ball. 2. Problem 62. Also, answer this question: Did the momentum of the system (skateboard + boy) remain constant during the time the boy was jumping off the skateboard? Explain. If it remained constant, make an argument for why it remained constant. If it did not remain constant, explain what caused it to change.
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This note was uploaded on 06/22/2009 for the course PHYS 1101 taught by Professor Richardson, b during the Fall '08 term at Cornell.

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HW6 solutions - HomeWork 6 solutions 1. Chapter 7 problem 6...

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