This preview shows pages 1–2. Sign up to view the full content.
This preview has intentionally blurred sections. Sign up to view the full version.View Full Document
Unformatted text preview: Bio2600: Introduction to Cell Biology Study Guide Chapter 13 13-1 Choice (d) is the correct answer. Oxidative phosphorylation produces about 28 ATP molecules. Choice (a) produces no ATP; choice (b) nets 2 ATP; choice (c) produces 1 GTP; and choice (e) produces no ATP. 13-2 Choice(c) is the correct answer. Choice (a) is untrue as the same overall amount of free energy is released by glucose oxidation, whatever the route. Choice (b) is untrue as a proportion of the energy released is still lost as heat. Choices (d) and (e) are untrue as the same amount of CO 2 will be released and O 2 consumed by the oxidation of glucose to CO 2 and H 2 O, whatever the route. 13-3 See Figure A13-6. Insert Figure A13-16 13-4 The net yield of glycolysis is two ATP molecules per glucose molecule because the steps that require ATP occur once per glucose molecule whereas those that generate ATP occur twice per glucose molecule. This is because Step 4, catalyzed by aldolase, breaks down a 6-carbon intermediate into two 3-carbon intermediates. Each 3-carbon intermediate is processed by the remaining steps and thus Steps 7 and 10 occur twice per original 6-carbon glucose molecule. 13-5 Choice (a) is the correct answer. It helps drive the uptake of glucose from outside the cell. Choice (b) is incorrect since the phosphate transferred to the glucose is not held by a high-energy covalent bond. Choice (c) is incorrect since the reaction converts ATP to ADP, which is not useful as an energy source for most cellular reactions, even though it still has one high-energy bond. Choice (d) is incorrect since the next enzyme in the pathway is phosphoglucose isomerase, not phosphofructokinase. Choice (e) is incorrect since the reaction does not involve oxidation of carbon nor does it yield usable energy....
View Full Document
- Winter '08
- cell biology