F18105_E1.pdf - CHEM 105 E1 Constants and equations Speed of light c = 2.997x108ms-1 1 J = 1 kg\u2219m2\u2219s-2 mass of e me=9.11x10-31 kg = \u210e \u2219 \u210e \u210e

F18105_E1.pdf - CHEM 105 E1 Constants and equations Speed...

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CHEM 105 E1 F18 Name Constants and equations: Speed of light: c = 2.997x108ms-1Plank’s constant: h=6.626x10-34J∙s 1 J = 1 kg∙m2∙s-2charge of an e-: e = 1.602x10-19C mass of e-: me=9.11x10-31kg mass of p+: mp=1.67x10-27kg 𝐸𝐸=ℎ ∙ 𝜈𝜈Avogadro’s constant: NA= 6.022x1023mol-1DeBroglie Relation: 𝜆𝜆=𝑚𝑚∙v=𝑝𝑝𝐸𝐸=2.18 × 10−18𝐽𝐽 ∙ �𝑍𝑍2𝑛𝑛2∆𝐸𝐸=2.18 × 10−18𝐽𝐽 ∙ �𝑍𝑍2𝑛𝑛𝑓𝑓2𝑍𝑍2𝑛𝑛𝑖𝑖2c = λνPV=nRT 𝑢𝑢𝑟𝑟𝑚𝑚𝑟𝑟=3𝑅𝑅𝑅𝑅𝑀𝑀𝐸𝐸𝐸𝐸𝐸𝐸𝐸𝐸𝑟𝑟𝐸𝐸𝐸𝐸𝑛𝑛𝑅𝑅𝑅𝑅𝑅𝑅𝑅𝑅𝐺𝐺𝑅𝑅𝑟𝑟1𝐸𝐸𝐸𝐸𝐸𝐸𝐸𝐸𝑟𝑟𝐸𝐸𝐸𝐸𝑛𝑛𝑅𝑅𝑅𝑅𝑅𝑅𝑅𝑅𝐺𝐺𝑅𝑅𝑟𝑟2= �𝑀𝑀𝑀𝑀2�𝑀𝑀𝑀𝑀1�𝑃𝑃+𝑎𝑎 �𝑛𝑛𝑉𝑉2(𝑉𝑉 − 𝑛𝑛𝑛𝑛) =𝑛𝑛𝑛𝑛𝑛𝑛𝑛𝑛= 0.08206𝐿𝐿∙𝑅𝑅𝑅𝑅𝑚𝑚𝑚𝑚𝐸𝐸𝑚𝑚∙𝐾𝐾= 8.31451𝐽𝐽𝑚𝑚𝐸𝐸𝑚𝑚∙𝐾𝐾𝐾𝐾𝐸𝐸=12𝑚𝑚u2=32𝑛𝑛𝑛𝑛𝑝𝑝𝑝𝑝=𝑝𝑝𝐾𝐾𝑅𝑅+𝑙𝑙𝑙𝑙𝑙𝑙 �𝐴𝐴𝑝𝑝𝐴𝐴𝑝𝑝𝑝𝑝𝑝𝑝=𝑝𝑝𝐾𝐾𝑏𝑏+𝑙𝑙𝑙𝑙𝑙𝑙 �𝑝𝑝𝐴𝐴𝐴𝐴Colligative properties: Π=iCRT T=iKfpm ΔT=iKbpm PA=PAoXAHenry’s Law: C=kP Arrhenius equation: k=Ae-Ea/RTand A=pz 1storder rate law: ln[A] = -kt +ln[A]02ndorder rate law: 1/[A]= kt + 1/[A]01stLaw of Thermodynamics: ΔEtotal= ΔEsys+ ΔEsur=0 2ndLaw of Thermodynamics: Stotal = Ssys+Ssur ≥ 0and Ssur = Esur/Tand Swt = 0 3rdLaw of Thermodynamics: 0K= 0 for pure, crystalline substances G=H-TS rG = rG° + RTlnQ Nernst Equation:E=Eo-(0.0592V mol e-/n)logQ G=-nFE rG°=-RTlnK F = 96,500 C/mol e-Score
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CHEM 105 E1 F18 Network ID Name Please write a capital letter of the best response for each question (1-7) in each box. For questions 8-11, place any final answers in boxes provided and be sure to use appropriate units and significant figures. 1 2 3 4 5 6 7 1. As part of the calibration of a new laboratory balance, a 1.000-g mass is weighed with the following results: Trial Mass (g) 1 1.201 ± 0.001 2 1.202 ± 0.001 3 1.200 ± 0.001 The balance is: A) Both accurate and precise.
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