Quiz__8_-_March_28st,_2007-KEY

# Quiz__8_-_March_28st,_2007-KEY - b =(12 Sin 65(sin 50 b =...

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Math 1180 Quiz #8 March 28th, 2007 Name:__________________________________________________________________ Please answer the following questions to the best of your ability. Print clearly and present your solution as concisely as possible. Thanks and good luck. Law of sines: C c B b A a sin sin sin = = Law of cosines: A c b c b a cos * * * 2 2 2 2 - + = B c a c a b cos * * * 2 2 2 2 - + = C b a b a c cos * * * 2 2 2 2 - + = 1. Use the law of sines to solve the following triangle ABC (5 points). 2. Use the law of cosines to solve the following triangle ABC (5 points). . C A B a = ? Solution: Find / C 180 - (65 + 50) = 65 Thus / C = 65 o which makes the triangle isosceles To find b: (Sin 65)/b = (Sin 50)/12 b Sin 50 = 12 Sin 65
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Unformatted text preview: b = (12 Sin 65)/(sin 50) b = 14.2 Since / C = / B, c = b, so c = 14.2 For unknown length a: 539 . 3 5254 . 12 5254 . 12 ) 68 cos( * 5 . 2 * 6 . 3 * 2 5 . 2 6 . 3 2 2 2 = = =-+ = a a o For unknown angle C : o C C C C 987 . 40 ) 75486 . ( cos cos 75486 . cos * 4808 . 25 96 . 12 5245 . 12 25 . 6 cos * 6 . 3 * 539 . 3 * 2 6 . 3 539 . 3 5 . 2 1 2 2 2 = = =-+ =-+ =-For unknown angle B : o B B B B 816 . 70 ) 328597 . ( cos cos 328597 . cos * 695 . 17 25 . 6 5245 . 12 96 . 12 cos * 5 . 2 * 539 . 3 * 2 5 . 2 539 . 3 6 . 3 1 2 2 2 = = =-+ =-+ =-...
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