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Unformatted text preview: Sol6 1. a. P(0 Z 2.17) = (2.17)  (0) = .4850 b. (1)  (0) = .3413 c. (0)  (2.50) = .4938 d. (2.50)  (2.50) = .9876 e. (1.37) = .9147 f. P( 1.75 < Z) + [1 P(Z < 1.75)] = 1  (1.75) = .9599 g. (2)  (1.50) = .9104 h. (2.50)  (1.37) = .0791 i. 1  (1.50) = .0668 j. P( Z 2.50 ) = P( 2.50 Z 2.50) = (2.50)  (2.50) = .9876 2. a. .9838 is found in the 2.1 row and the .04 column of the standard normal table so c = 2.14. b. P(0 Z c) = .291 (c) = .7910 c = .81 c. P(c Z) = .121 1  P(c Z) = P(Z < c) = (c) = 1  .121 = .8790 c = 1.17 d. P(c Z c) = (c)  (c) = (c) (1  (c)) = 2 (c) 1 (c) = .9920 c = .97 e. P( c  Z  ) = .016 1  .016 = .9840 = 1 P(c  Z  ) = P(  Z  < c ) = P(c < Z < c) = (c)  (c) = 2 (c) 1 (c) = .9920 c = 2.41 3....
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This homework help was uploaded on 01/31/2008 for the course ENGR 361 taught by Professor Eisenstein during the Fall '04 term at Drexel.
 Fall '04
 Eisenstein

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